(x+3)^2=3(x+5)

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Solution for (x+3)^2=3(x+5) equation: 



(x+3)^2=3(x+5)

We move all terms to the left:

(x+3)^2-(3(x+5))=0



We calculate terms in parentheses: -(3(x+5)), so:

3(x+5)

We multiply parentheses

3x+15

Back to the equation:

-(3x+15)



We get rid of parentheses

(x+3)^2-3x-15=0

We add all the numbers together, and all the variables

-3x+(x+3)^2-15=0

We move all terms containing x to the left, all other terms to the right

-3x+(x+3)^2=15

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